How many geometrical isomers can be written for the compound $CH_3-CH=CH-CH=CH-CH=CH-Cl$?
- A$2$
- B$4$
- C$6$
- D$8$
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The relation between $(A)$ and $(B)$ is:
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How many geometrical isomers are possible for this compound?
How many geometrical isomers are possible for this compound?
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View SolutionIn the given reaction: $C_6H_5-CH=O \xrightarrow{NH_2OH/H^{+}} [X]$. $[X]$ will be:
The alkenes which exhibit $cis, trans$ isomerism from the following are:
a) $YXC=CXZ$
b) $X_2C=CX_2$
c) $YXC=CXY$
d) $YXC=CWZ$
e) $X_2C=CXY$
a) $YXC=CXZ$
b) $X_2C=CX_2$
c) $YXC=CXY$
d) $YXC=CWZ$
e) $X_2C=CXY$
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